[Gretl-users] Simple variable generation question

Data Analytics Corp. walt at dataanalyticscorp.com
Wed Mar 7 17:10:11 EST 2012


Perfect -- thanks

Walt

On 3/7/2012 4:23 PM, Allin Cottrell wrote:
> On Wed, 7 Mar 2012, Data Analytics Corp. wrote:
>
>> Thanks.  This will work for my current problem.  But what if I have a 
>> very large data set and the econ observations are scattered 
>> throughout the data set?  This won't work.
>
> Put your string-valued categorical variable somewhere other than the 
> first column, export the data as CSV, and open the CSV in gretl. Then 
> gretl won't interpret that variable as an observation label, but will 
> code it numerically.
>
> Allin Cottrell
>>
>> On 3/7/2012 3:54 PM, Allin Cottrell wrote:
>>> On Wed, 7 Mar 2012, Data Analytics Corp. wrote:
>>>
>>>> I have car data that I imported from excel.  The first column of the
>>>> excel worksheet has a car designation label: econ or prestige.  The
>>>> first 40 observations are econ cars and the next 40 are prestige cars.
>>>> In Gretl, the designation appears as a row label.  I'd like to subset
>>>> the data to model the econ cars.  I tried to create a dummy variable,
>>>> seg, as
>>>>
>>>> seg = (obs == "econ")
>>>
>>> Try seg = (obs < 41)
>>>
>>> Allin Cottrell
>>>
>>>
>>>
>>
>>
>



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